A parallel plate capacitor with plate separation $d$ and plate area $A$ is connected to a battery of electromotive force $V$. If the dielectric cons ant of the material between the plates is $kappa$, the capaci ance of the capacitor is given by $C = \frac{kappa epsilon_0 A}{d}$. If the battery is disconnected and a charge $Q$ is removed from the capacitor, the electric field between the plates is given by $E = \frac{Q}{kappa epsilon_0 A}$. What is the energy stored in the capacitor when the charge is $Q$?

Question

A parallel plate capacitor with plate separation $d$ and plate area $A$ is connected to a battery of electromotive force $V$. If the dielectric cons	ant of the material between the plates is $kappa$, the capaci	ance of the capacitor is given by $C = \frac{kappa epsilon_0 A}{d}$. If the battery is disconnected and a charge $Q$ is removed from the capacitor, the electric field between the plates is given by $E = \frac{Q}{kappa epsilon_0 A}$. What is the energy stored in the capacitor when the charge is $Q$?

Accepted Answer

0.5\kappa\epsilon_0\frac{Q^2}{A}

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