Post Utme Rsu 2018 Mathematics Question 36

Practice objective / multiple choice question 36 from the 2018 Post Utme Rsu Mathematics examination.

Post Utme Rsu 2018 Mathematics Objective / Multiple Choice

Question 36 POST_UTME_RSU • 2018 • MATHEMATICS • objective

Let ( f(x) = \(\frac{x^2 - 4}{x - 2}\)\)) ). Find lim_{x \to 2} f\( x \\() ). Find lim_{x to 2} f\ ) using the chain rule.

A. \lim_{x \to 2}\(f(x) =\)\(\frac{0}{0}\)\)

B. \lim_{x \to 2}\(f(x) =\)\(\frac{4}{0}\)\)

Correct Answer C. \lim_{x \to 2}\(f(x) =\)\(\frac{0}{0}\)\)

D. \lim_{x \to 2}\(f(x) =\)\(\frac{4}{2}\)\)

Correct Answer

Correct Option:

\lim_{x \to 2}\(f(x) =\)\(\frac{0}{0}\)\)

This is Post Utme Rsu 2018 Mathematics Question 36. It is one of the objective questions from the 2018 Post Utme Rsu Mathematics examination.

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