Post Utme Rhema University 2019 Biology Question 38

Practice objective / multiple choice question 38 from the 2019 Post Utme Rhema University Biology examination.

Post Utme Rhema University 2019 Biology Objective / Multiple Choice
Question 38 POST_UTME_RHEMA_UNIVERSITY • 2019 • BIOLOGY • objective

A solution of glu\cose (C6H12O6) is titrated with a solution of potassium permanganate (KMnO4). The reaction is as follows: C6H12O6 + 6O2 → 6CO2 + 6H2O. If 25.0 mL of 0.100 M KMnO4 is required to titrate 25.0 mL of 0.100 M glu\cose, what is the number of moles of glu\cose that reacted?

Answer Options

A. 0.0015
Correct Answer B. 0.0030
C. 0.0045
D. 0.0060
Correct Answer
B
Correct Option:
0.0030

About This Question

This is Post Utme Rhema University 2019 Biology Question 38. It is one of the objective questions from the 2019 Post Utme Rhema University Biology examination.

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