Post Utme Osustech 2019 Mathematics Question 22

Practice objective / multiple choice question 22 from the 2019 Post Utme Osustech Mathematics examination.

Post Utme Osustech 2019 Mathematics Objective / Multiple Choice
Question 22 POST_UTME_OSUSTECH • 2019 • MATHEMATICS • objective

Solve for y in the equation \(y = \frac{1}{2} x + 3 \\)^2 - 2 ).

Answer Options

Correct Answer A. \(y =\)\(\frac{1}{2}\)\) \(x^2 + 3x - 1\)
B. \(y =\)\(\frac{1}{2}\)\) \(x^2 + 3x + 1\)
C. \(y =\)\(\frac{1}{2}\)\) \(x^2 - 3x - 1\)
D. \(y =\)\(\frac{1}{2}\)\) \(x^2 - 3x + 1\)
Correct Answer
A
Correct Option:
\(y =\)\(\frac{1}{2}\)\) \(x^2 + 3x - 1\)

About This Question

This is Post Utme Osustech 2019 Mathematics Question 22. It is one of the objective questions from the 2019 Post Utme Osustech Mathematics examination.

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