A projectile is launched from the ground with an initial velocity $v_0$ at an angle $ heta$ above the horizontal. The projectile's range $R$ is given by $R = \frac{v_0^2 \sin 2 heta}{g}$. If the initial velocity is doubled to $2v_0$, what is the new range $R_{new}$?

Question

A projectile is launched from the ground with an initial velocity $v_0$ at an angle $	heta$ above the horizontal. The projectile's range $R$ is given by $R = \frac{v_0^2 \sin 2	heta}{g}$. If the initial velocity is doubled to $2v_0$, what is the new range $R_{new}$?

Accepted Answer

\frac{$ 2v_0 $^2 \sin 2\theta}{g}

Post Utme Osustech 2017 Physics Question 25

A projectile is launched from the ground with an initial velocity $v_0$ at an angle $\theta$ above the horizontal. The projectile's range $R$ is given by $R = \frac{v_0^2 \sin 2\theta}{g}$. If the initial velocity is doubled to $2v_0$, what is the new range $R_{new}$?

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