Post Utme Mountain Top University 2019 Physics Question 14

Practice objective / multiple choice question 14 from the 2019 Post Utme Mountain Top University Physics examination.

Post Utme Mountain Top University 2019 Physics Objective / Multiple Choice
Question 14 POST_UTME_MOUNTAIN_TOP_UNIVERSITY • 2019 • PHYSICS • objective

A simple harmonic motion has a maximum displacement of 2 m and a period of 4 seconds. If the motion starts from its equilibrium position, what is the equation of motion?

Answer Options

Correct Answer A. x(t) = 2 \sin\( \frac{\pi}{2}t \)
B. x(t) = 2 \sin\( \frac{\pi}{4}t \)
C. x(t) = 2 \sin\( \frac{\pi}{8}t \)
D. x(t) = 2 \sin\( \frac{\pi}{16}t \)
Correct Answer
A
Correct Option:
x(t) = 2 \sin\( \frac{\pi}{2}t \)

About This Question

This is Post Utme Mountain Top University 2019 Physics Question 14. It is one of the objective questions from the 2019 Post Utme Mountain Top University Physics examination.

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