Post Utme Lautech 2018 Physics Question 21

Practice objective / multiple choice question 21 from the 2018 Post Utme Lautech Physics examination.

Post Utme Lautech 2018 Physics Objective / Multiple Choice
Question 21 POST_UTME_LAUTECH • 2018 • PHYSICS • objective

A particle of mass $m$ is moving in a circular orbit of radius $r$ under the influence of a central force given by $F(r) = -\frac{k}{r^2}$. If the particle's angular momentum is $L = 2mvr$, find the total energy of the particle.

Answer Options

A. $\frac{1}{2}mv^2 + \frac{k}{r}$
Correct Answer B. $\frac{1}{2}mv^2 - \frac{k}{r}$
C. $-\frac{1}{2}mv^2 - \frac{k}{r}$
D. $-\frac{1}{2}mv^2 + \frac{k}{r}$
Correct Answer
B
Correct Option:
$\frac{1}{2}mv^2 - \frac{k}{r}$

About This Question

This is Post Utme Lautech 2018 Physics Question 21. It is one of the objective questions from the 2018 Post Utme Lautech Physics examination.

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