A particle of mass $m$ is moving in a circular path of radius $r$ with a cons ant speed $v$. The particle is subject to a centripetal force $F_c$ given by $F_c = \frac{mv^2}{r}$. If the particle's speed is doubled, what happens to the centripetal force?

Question

A particle of mass $m$ is moving in a circular path of radius $r$ with a cons	ant speed $v$. The particle is subject to a centripetal force $F_c$ given by $F_c = \frac{mv^2}{r}$. If the particle's speed is doubled, what happens to the centripetal force?

Accepted Answer

The centripetal force increases by a factor of 2.

Post Utme Lasu 2024 Physics Question 26

A particle of mass $m$ is moving in a circular path of radius $r$ with a cons\tant speed $v$. The particle is subject to a centripetal force $F_c$ given by $F_c = \frac{mv^2}{r}$. If the particle's speed is doubled, what happens to the centripetal force?

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