Post Utme Lasu 2018 Physics Question 31

Practice objective / multiple choice question 31 from the 2018 Post Utme Lasu Physics examination.

Post Utme Lasu 2018 Physics Objective / Multiple Choice
Question 31 POST_UTME_LASU • 2018 • PHYSICS • objective

A particle of mass $m$ is moving in a circular orbit of radius $r$ under the influence of a central force given by $F(r) = -\frac{k}{r^2}$. If the particle's speed is $v$, what is its total energy?

Answer Options

A. $\frac{1}{2}mv^2$
B. $\frac{1}{2}mv^2 + \frac{k}{r}$
Correct Answer C. $\frac{1}{2}mv^2 - \frac{k}{r}$
D. $\frac{1}{2}mv^2 + \frac{k}{r^2}$
Correct Answer
C
Correct Option:
$\frac{1}{2}mv^2 - \frac{k}{r}$

About This Question

This is Post Utme Lasu 2018 Physics Question 31. It is one of the objective questions from the 2018 Post Utme Lasu Physics examination.

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