Post Utme Ksu 2021 Chemistry Question 24

Practice objective / multiple choice question 24 from the 2021 Post Utme Ksu Chemistry examination.

Post Utme Ksu 2021 Chemistry Objective / Multiple Choice

Question 24 POST_UTME_KSU • 2021 • CHEMISTRY • objective

A solution of 0.1 M NaOH is titrated with 0.1 M HCl. The pH of the solution at the equivalence point is 7. Calculate the pH of the solution at the half-equivalence point.

Correct Answer A. \( pH = \frac{1}{2} \times pH_{eq} \)

B. \( pH = \frac{1}{2} \times pH_{initial} \)

C. \( pH = pH_{eq} - \frac{1}{2} \times pH_{initial} \)

D. \( pH = pH_{eq} + \frac{1}{2} \times pH_{initial} \)

Correct Answer

Correct Option:

\( pH = \frac{1}{2} \times pH_{eq} \)

This is Post Utme Ksu 2021 Chemistry Question 24. It is one of the objective questions from the 2021 Post Utme Ksu Chemistry examination.

You've seen a preview, but there are thousands more questions plus AI tutor to break down complex solutions.

Unlock Full Access Available for Android & Windows

Chat with Support