Post Utme Ksu 2018 Physics Question 16

Practice objective / multiple choice question 16 from the 2018 Post Utme Ksu Physics examination.

Post Utme Ksu 2018 Physics Objective / Multiple Choice
Question 16 POST_UTME_KSU • 2018 • PHYSICS • objective

A particle of mass $m$ is moving in a circular orbit of radius $r$ under the influence of a central force given by $F(r) = -\frac{k}{r^2}$, where $k$ is a positive cons\tant. If the particle's angular momentum is $L = 2mr^2 omega$, find the total energy of the particle in terms of $m$, $r$, and $k$.

Answer Options

Correct Answer A. \frac{1}{2} m r^2 \omega^2 - \frac{k}{r}
B. \frac{1}{2} m r^2 \omega^2 + \frac{k}{r}
C. \frac{1}{2} m r^2 \omega^2
D. -\frac{k}{r}
Correct Answer
A
Correct Option:
\frac{1}{2} m r^2 \omega^2 - \frac{k}{r}

About This Question

This is Post Utme Ksu 2018 Physics Question 16. It is one of the objective questions from the 2018 Post Utme Ksu Physics examination.

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