Post Utme Joseph Ayo Babalola University 2020 Mathematics Question 27

Practice objective / multiple choice question 27 from the 2020 Post Utme Joseph Ayo Babalola University Mathematics examination.

Post Utme Joseph Ayo Babalola University 2020 Mathematics Objective / Multiple Choice
Question 27 POST_UTME_JOSEPH_AYO_BABALOLA_UNIVERSITY • 2020 • MATHEMATICS • objective

Solve the equation \(\sin^2 x + \cos^2 x = 1\) for x in the interval [0, 2\pi].

Answer Options

Correct Answer A. \(x =\)\(\frac{\pi}{4}\)\)
B. \(x =\)\(\frac{3\pi}{4}\)\)
C. \(x =\)\(\frac{5\pi}{4}\)\)
D. \(x =\)\(\frac{7\pi}{4}\)\)
Correct Answer
A
Correct Option:
\(x =\)\(\frac{\pi}{4}\)\)

About This Question

This is Post Utme Joseph Ayo Babalola University 2020 Mathematics Question 27. It is one of the objective questions from the 2020 Post Utme Joseph Ayo Babalola University Mathematics examination.

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