Post Utme Ims U 2019 Mathematics Question 26

Practice objective / multiple choice question 26 from the 2019 Post Utme Ims U Mathematics examination.

Post Utme Ims U 2019 Mathematics Objective / Multiple Choice
Question 26 POST_UTME_IMS_U • 2019 • MATHEMATICS • objective

Find the area under the curve \(y = \frac{1}{2}x^2 + 3x - 2\) from \(x = 0\) to \(x = 4\).

Answer Options

Correct Answer A. \(\frac{1}{2} \left \frac{4^3}{3} + 3 \cdot 4^2 - 2 \cdot 4 \right \\) - left\(\frac{1}{2} \cdot 0^2 + 3 \cdot 0 - 2 \right\) )
B. \(\frac{1}{2} \left \frac{4^3}{3} + 3 \cdot 4^2 - 2 \cdot 4 \right \\) - left\(\frac{1}{2} \cdot 0^2 + 3 \cdot 0 - 2 \right\) + \(\frac{1}{2}\)\) )
C. \(\frac{1}{2} \left \frac{4^3}{3} + 3 \cdot 4^2 - 2 \cdot 4 \right \\) - left\(\frac{1}{2} \cdot 0^2 + 3 \cdot 0 - 2 \right\) - \(\frac{1}{2}\)\) )
D. \(\frac{1}{2} \left \frac{4^3}{3} + 3 \cdot 4^2 - 2 \cdot 4 \right \\) - left\(\frac{1}{2} \cdot 0^2 + 3 \cdot 0 - 2 \right\) + \(\frac{1}{2}\)\) )
Correct Answer
A
Correct Option:
\(\frac{1}{2} \left \frac{4^3}{3} + 3 \cdot 4^2 - 2 \cdot 4 \right \\) - left\(\frac{1}{2} \cdot 0^2 + 3 \cdot 0 - 2 \right\) )

About This Question

This is Post Utme Ims U 2019 Mathematics Question 26. It is one of the objective questions from the 2019 Post Utme Ims U Mathematics examination.

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