Post Utme Greenfield University 2024 Chemistry Question 26

Practice objective / multiple choice question 26 from the 2024 Post Utme Greenfield University Chemistry examination.

Post Utme Greenfield University 2024 Chemistry Objective / Multiple Choice
Question 26 POST_UTME_GREENFIELD_UNIVERSITY • 2024 • CHEMISTRY • objective

The rate cons\tant (k) of a first-order reaction is given by the equation: k = Ae^\( -Ea/RT \). If the activation energy (Ea) is 100 kJ/mol, the gas cons\tant (R) is 8.314 J/mol*K, and the temperature (T) is 300 K, calculate the value of k when A = 2.5 x 10^\( -3 \) s^\( -1 \).

Answer Options

A. 1.45 x 10^\( -3 \) s^\( -1 \)
Correct Answer B. 2.45 x 10^\( -3 \) s^\( -1 \)
C. 3.45 x 10^\( -3 \) s^\( -1 \)
D. 4.45 x 10^\( -3 \) s^\( -1 \)
Correct Answer
B
Correct Option:
2.45 x 10^\( -3 \) s^\( -1 \)

About This Question

This is Post Utme Greenfield University 2024 Chemistry Question 26. It is one of the objective questions from the 2024 Post Utme Greenfield University Chemistry examination.

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