Post Utme Futa 2019 Physics Question 14

Practice objective / multiple choice question 14 from the 2019 Post Utme Futa Physics examination.

Post Utme Futa 2019 Physics Objective / Multiple Choice

Question 14 POST_UTME_FUTA • 2019 • PHYSICS • objective

A particle of mass $m$ is moving in a potential $U(x) = kx^2$. If the particle is released from rest at $x = 0$, what is the total energy of the particle?

Correct Answer A. $ E = \frac{1}{2}mv^2 + U(x) $

B. $ E = \frac{1}{2}mv^2 - U(x) $

C. $ E = \frac{1}{2}mv^2 $

D. $ E = -U(x) $

Correct Answer

Correct Option:

$ E = \frac{1}{2}mv^2 + U(x) $

This is Post Utme Futa 2019 Physics Question 14. It is one of the objective questions from the 2019 Post Utme Futa Physics examination.

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