A parallel plate capacitor has plates of area $A$ and separation $d$. The capaci ance is given by $C = \frac{epsilon_0 A}{d}$. If the area of the plates is doubled and the separation is halved, what is the new capaci ance?

Question

A parallel plate capacitor has plates of area $A$ and separation $d$. The capaci	ance is given by $C = \frac{epsilon_0 A}{d}$. If the area of the plates is doubled and the separation is halved, what is the new capaci	ance?

Accepted Answer

$ C' = 4 \frac{\epsilon_0 A}{d} $

Post Utme Esut 2024 Physics Question 23

A parallel plate capacitor has plates of area $A$ and separation $d$. The capaci\tance is given by $C = \frac{epsilon_0 A}{d}$. If the area of the plates is doubled and the separation is halved, what is the new capaci\tance?

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