Post Utme Crawford University 2020 Mathematics Question 11

Practice objective / multiple choice question 11 from the 2020 Post Utme Crawford University Mathematics examination.

Post Utme Crawford University 2020 Mathematics Objective / Multiple Choice
Question 11 POST_UTME_CRAWFORD_UNIVERSITY • 2020 • MATHEMATICS • objective

Find the area under the curve \(y = \frac{1}{2}x^2 + 3x - 2\) from \(x = 0\) to \(x = 4\).

Answer Options

Correct Answer A. \(\frac{1}{2} \left \frac{4^3}{3} + 3 \cdot 4^2 - 2 \cdot 4 \right \\) - \left\(\frac{1}{2} \cdot 0^2 + 3 \cdot 0 - 2 \right\)
B. \(\frac{1}{2} \left \frac{4^3}{3} + 3 \cdot 4^2 - 2 \cdot 4 \right \\) + \left\(\frac{1}{2} \cdot 0^2 + 3 \cdot 0 - 2 \right\)
C. \(\frac{1}{2} \left \frac{4^3}{3} + 3 \cdot 4^2 - 2 \cdot 4 \right \\)
D. \(\frac{1}{2} \left \frac{4^3}{3} + 3 \cdot 4^2 - 2 \cdot 4 \right \\) + 2 \)
Correct Answer
A
Correct Option:
\(\frac{1}{2} \left \frac{4^3}{3} + 3 \cdot 4^2 - 2 \cdot 4 \right \\) - \left\(\frac{1}{2} \cdot 0^2 + 3 \cdot 0 - 2 \right\)

About This Question

This is Post Utme Crawford University 2020 Mathematics Question 11. It is one of the objective questions from the 2020 Post Utme Crawford University Mathematics examination.

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