Post Utme Crawford University 2019 Mathematics Question 29

Practice objective / multiple choice question 29 from the 2019 Post Utme Crawford University Mathematics examination.

Post Utme Crawford University 2019 Mathematics Objective / Multiple Choice
Question 29 POST_UTME_CRAWFORD_UNIVERSITY • 2019 • MATHEMATICS • objective

Find the derivative of the function ( f(x) = \(\frac{1}{x^2 + 1}\)\)\) ) using the chain rule.

Answer Options

Correct Answer A. ( f'\((x) =\)\(\frac{-2x}{x^2 + 1\) ^2}\)\) )
B. ( f'\((x) =\)\(\frac{2x}{x^2 + 1\) ^2}\)\) )
C. ( f'\((x) =\)\(\frac{-x}{x^2 + 1\) ^2}\)\) )
D. ( f'\((x) =\)\(\frac{x}{x^2 + 1\) ^2}\)\) )
Correct Answer
A
Correct Option:
( f'\((x) =\)\(\frac{-2x}{x^2 + 1\) ^2}\)\) )

About This Question

This is Post Utme Crawford University 2019 Mathematics Question 29. It is one of the objective questions from the 2019 Post Utme Crawford University Mathematics examination.

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