Post Utme Christopher University 2020 Physics Question 5

Practice objective / multiple choice question 5 from the 2020 Post Utme Christopher University Physics examination.

Post Utme Christopher University 2020 Physics Objective / Multiple Choice
Question 5 POST_UTME_CHRISTOPHER_UNIVERSITY • 2020 • PHYSICS • objective

A projectile is launched from the origin with an initial velocity of $v_0 = 20$ m/s at an angle of $\theta = 45^\circ$ above the horizontal. What is the maximum height reached by the projectile?

Answer Options

Correct Answer A. \( \frac{200^2 \sin^2 45^\circ}{2 \cdot 9.8} \)
B. \( \frac{200^2 \cos^2 45^\circ}{2 \cdot 9.8} \)
C. \( \frac{200^2 \sin^2 45^\circ}{2 \cdot 10} \)
D. \( \frac{200^2 \cos^2 45^\circ}{2 \cdot 10} \)
Correct Answer
A
Correct Option:
\( \frac{200^2 \sin^2 45^\circ}{2 \cdot 9.8} \)

About This Question

This is Post Utme Christopher University 2020 Physics Question 5. It is one of the objective questions from the 2020 Post Utme Christopher University Physics examination.

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