Post Utme Christopher University 2019 Physics Question 36

Practice objective / multiple choice question 36 from the 2019 Post Utme Christopher University Physics examination.

Post Utme Christopher University 2019 Physics Objective / Multiple Choice
Question 36 POST_UTME_CHRISTOPHER_UNIVERSITY • 2019 • PHYSICS • objective

A particle of mass $m$ is moving in a circular orbit of radius $R$ under the influence of a central force given by $F(r) = \frac{k}{r^2}$, where $k$ is a cons\tant. If the particle's speed is $v$, what is the total energy of the particle?

Answer Options

A. $\frac{1}{2}mv^2$
Correct Answer B. $\frac{1}{2}mv^2 - \frac{k}{R}$
C. $\frac{1}{2}mv^2 + \frac{k}{R}$
D. $\frac{1}{2}mv^2 - \frac{k}{R^2}$
Correct Answer
B
Correct Option:
$\frac{1}{2}mv^2 - \frac{k}{R}$

About This Question

This is Post Utme Christopher University 2019 Physics Question 36. It is one of the objective questions from the 2019 Post Utme Christopher University Physics examination.

Master the Exam!

You've seen a preview, but there are thousands more questions plus AI tutor to break down complex solutions.

Unlock Full Access Available for Android & Windows
Chat with Support