Post Utme Bsu 2017 Physics Question 36

Practice objective / multiple choice question 36 from the 2017 Post Utme Bsu Physics examination.

Post Utme Bsu 2017 Physics Objective / Multiple Choice
Question 36 POST_UTME_BSU • 2017 • PHYSICS • objective

A particle of mass $m$ is projected from the origin with an initial velocity $mathbf{v}_0 = v_0 \cos \theta mathbf{i} + v_0 \sin \theta mathbf{j}$, where $v_0$ is the magnitude of the initial velocity and $\theta$ is the angle of projection. If the particle is subject to a uniform gravitational field of strength $g$, find the equation of the trajectory of the particle in the $xy$-plane.

Answer Options

Correct Answer A. \( y = \frac{v_0^2}{2g} \sin^2 \theta - \frac{gx^2}{2v_0^2 \cos^2 \theta} \)
B. \( y = \frac{v_0^2}{2g} \sin^2 \theta + \frac{gx^2}{2v_0^2 \cos^2 \theta} \)
C. \( y = \frac{v_0^2}{2g} \sin^2 \theta - \frac{gx^2}{2v_0^2 \cos^2 \theta} + \frac{v_0^2}{2g} \)
D. \( y = \frac{v_0^2}{2g} \sin^2 \theta + \frac{gx^2}{2v_0^2 \cos^2 \theta} - \frac{v_0^2}{2g} \)
Correct Answer
A
Correct Option:
\( y = \frac{v_0^2}{2g} \sin^2 \theta - \frac{gx^2}{2v_0^2 \cos^2 \theta} \)

About This Question

This is Post Utme Bsu 2017 Physics Question 36. It is one of the objective questions from the 2017 Post Utme Bsu Physics examination.

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