Post Utme Bowen University 2020 Mathematics Question 8

Practice objective / multiple choice question 8 from the 2020 Post Utme Bowen University Mathematics examination.

Post Utme Bowen University 2020 Mathematics Objective / Multiple Choice
Question 8 POST_UTME_BOWEN_UNIVERSITY • 2020 • MATHEMATICS • objective

Find the equation of the tangent line to the curve \(\frac{x^2}{a\\(tangent line to the curve (\)^2}\)\) + \(\frac{y^2}{b)^2}\)\) = 1 at the point \\()^2})\(a\sqrt{2}, b\).

Answer Options

Correct Answer A. \(y =\)\(\frac{b}{a}\)\)\(\sqrt{x - a}\)
B. \(y =\)\(\frac{b}{a}\)\)\(\sqrt{a - x}\)
C. \(y =\)\(\frac{b}{a}\)\)\(\sqrt{x + a}\)
D. \(y =\)\(\frac{b}{a}\)\)\(\sqrt{a + x}\)
Correct Answer
A
Correct Option:
\(y =\)\(\frac{b}{a}\)\)\(\sqrt{x - a}\)

About This Question

This is Post Utme Bowen University 2020 Mathematics Question 8. It is one of the objective questions from the 2020 Post Utme Bowen University Mathematics examination.

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