Post Utme Bowen University 2019 Chemistry Question 39

Practice objective / multiple choice question 39 from the 2019 Post Utme Bowen University Chemistry examination.

Post Utme Bowen University 2019 Chemistry Objective / Multiple Choice
Question 39 POST_UTME_BOWEN_UNIVERSITY • 2019 • CHEMISTRY • objective

A 50.0 mL sample of 0.100 M HCl is titrated with 0.100 M NaOH. If 25.0 mL of NaOH is required to reach the equivalence point, what is the pH of the solution after the addition of 25.0 mL of NaOH?

Answer Options

A. \( pH = 7 + \log_{10} left\( \frac{[OH^-]}{[H_2O]} \right \ \) )
Correct Answer B. \( pH = 7 - \log_{10} left\( \frac{[OH^-]}{[H_2O]} \right \ \) )
C. \( pH = 7 + \log_{10} left\( \frac{[H_2O]}{[OH^-]} \right \ \) )
D. \( pH = 7 - \log_{10} left\( \frac{[H_2O]}{[OH^-]} \right \ \) )
Correct Answer
B
Correct Option:
\( pH = 7 - \log_{10} left\( \frac{[OH^-]}{[H_2O]} \right \ \) )

About This Question

This is Post Utme Bowen University 2019 Chemistry Question 39. It is one of the objective questions from the 2019 Post Utme Bowen University Chemistry examination.

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