Post Utme Babcock University 2025 Chemistry Question 31

Practice objective / multiple choice question 31 from the 2025 Post Utme Babcock University Chemistry examination.

Post Utme Babcock University 2025 Chemistry Objective / Multiple Choice
Question 31 POST_UTME_BABCOCK_UNIVERSITY • 2025 • CHEMISTRY • objective

The rate cons\tant (k) of a first-order reaction is given by the equation: k = Ae^\( -Ea/RT \). If the activation energy (Ea) is 100 kJ/mol, the gas cons\tant (R) is 8.314 J/\( mol*K \), and the temperature (T) is 300 K, calculate the value of k when A = 2.5 x 10^6 s^\( -1 \) and R = 8.314 J/\( mol*K \).

Answer Options

A. 1.8 x 10^\( -5 \) s^\( -1 \)
Correct Answer B. 2.5 x 10^\( -5 \) s^\( -1 \)
C. 3.2 x 10^\( -5 \) s^\( -1 \)
D. 4.5 x 10^\( -5 \) s^\( -1 \)
Correct Answer
B
Correct Option:
2.5 x 10^\( -5 \) s^\( -1 \)

About This Question

This is Post Utme Babcock University 2025 Chemistry Question 31. It is one of the objective questions from the 2025 Post Utme Babcock University Chemistry examination.

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