Post Utme Babcock University 2023 Mathematics Question 23

Practice objective / multiple choice question 23 from the 2023 Post Utme Babcock University Mathematics examination.

Post Utme Babcock University 2023 Mathematics Objective / Multiple Choice
Question 23 POST_UTME_BABCOCK_UNIVERSITY • 2023 • MATHEMATICS • objective

Solve the trigonometric equation \(\sin^2 x + \cos^2 x = 1\) for ( x ) in the interval ( [0, 2pi] ).

Answer Options

Correct Answer A. \(x = \frac{\pi}{4}\)
B. \(x = \frac{\pi}{2}\)
C. \(x = \frac{3\pi}{4}\)
D. \(x = \frac{5\pi}{4}\)
Correct Answer
A
Correct Option:
\(x = \frac{\pi}{4}\)

About This Question

This is Post Utme Babcock University 2023 Mathematics Question 23. It is one of the objective questions from the 2023 Post Utme Babcock University Mathematics examination.

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