Post Utme Babcock University 2020 Chemistry Question 30

Practice objective / multiple choice question 30 from the 2020 Post Utme Babcock University Chemistry examination.

Post Utme Babcock University 2020 Chemistry Objective / Multiple Choice
Question 30 POST_UTME_BABCOCK_UNIVERSITY • 2020 • CHEMISTRY • objective

A 1.00 M solution of H2O is electrolyzed at 298 K. Calculate the number of moles of O2 gas produced at the anode after 2.50 hours, given that the cell potential is 2.00 V.

Answer Options

A. 0.0125 mol
B. 0.0250 mol
Correct Answer C. 0.0500 mol
D. 0.100 mol
Correct Answer
C
Correct Option:
0.0500 mol

About This Question

This is Post Utme Babcock University 2020 Chemistry Question 30. It is one of the objective questions from the 2020 Post Utme Babcock University Chemistry examination.

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