Post Utme Babcock University 2020 Chemistry Question 29

Practice objective / multiple choice question 29 from the 2020 Post Utme Babcock University Chemistry examination.

Post Utme Babcock University 2020 Chemistry Objective / Multiple Choice
Question 29 POST_UTME_BABCOCK_UNIVERSITY • 2020 • CHEMISTRY • objective

A 0.100 M solution of Fe2+ is electrolyzed at 298 K. Calculate the number of moles of Fe3+ produced at the anode after 2.50 hours, given that the cell potential is 2.00 V.

Answer Options

A. 0.0125 mol
B. 0.0250 mol
Correct Answer C. 0.0500 mol
D. 0.100 mol
Correct Answer
C
Correct Option:
0.0500 mol

About This Question

This is Post Utme Babcock University 2020 Chemistry Question 29. It is one of the objective questions from the 2020 Post Utme Babcock University Chemistry examination.

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