Post Utme Afe Babalola University 2017 Physics Question 6

Practice objective / multiple choice question 6 from the 2017 Post Utme Afe Babalola University Physics examination.

Post Utme Afe Babalola University 2017 Physics Objective / Multiple Choice
Question 6 POST_UTME_AFE_BABALOLA_UNIVERSITY • 2017 • PHYSICS • objective

A particle of mass $m$ is moving in a circular orbit of radius $r$ under the influence of a central force given by $F(r) = -\frac{k}{r^2}$, where $k$ is a positive cons\tant. If the particle's speed is $v$, what is its total energy $E$?

Answer Options

A. \frac{1}{2}mv^2 + \frac{k}{r}
Correct Answer B. \frac{1}{2}mv^2 - \frac{k}{r}
C. -\frac{1}{2}mv^2 + \frac{k}{r}
D. -\frac{1}{2}mv^2 - \frac{k}{r}
Correct Answer
B
Correct Option:
\frac{1}{2}mv^2 - \frac{k}{r}

About This Question

This is Post Utme Afe Babalola University 2017 Physics Question 6. It is one of the objective questions from the 2017 Post Utme Afe Babalola University Physics examination.

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