Post Utme Achievers University 2019 Mathematics Question 14

Practice objective / multiple choice question 14 from the 2019 Post Utme Achievers University Mathematics examination.

Post Utme Achievers University 2019 Mathematics Objective / Multiple Choice
Question 14 POST_UTME_ACHIEVERS_UNIVERSITY • 2019 • MATHEMATICS • objective

Solve the trigonometric equation \(2 \sin^2 x + 3 $1x - 1 = 0\) for ( 0 leq x leq 2 pi ).

Answer Options

Correct Answer A. \(\frac{\pi}{6}\)\), \(\frac{5\pi}{6}\)\)
B. \(\frac{\pi}{4}\)\), \(\frac{3\pi}{4}\)\)
C. \(\frac{\pi}{3}\)\), \(\frac{2\pi}{3}\)\)
D. \(\frac{\pi}{2}\)\), \pi
Correct Answer
A
Correct Option:
\(\frac{\pi}{6}\)\), \(\frac{5\pi}{6}\)\)

About This Question

This is Post Utme Achievers University 2019 Mathematics Question 14. It is one of the objective questions from the 2019 Post Utme Achievers University Mathematics examination.

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