POST UTME ABU 2025 Mathematics | Objective
Practice these randomly selected questions to test your readiness.
Question 1
Solve the system of equations \begin{align*} x + y &= 4 \ x - y &= 2 \end{align*}.
Question 2
Find the volume of the solid formed by revolving the region bounded by $y = x^2$, $y = 0$, and $x = 1$ about the $x$-axis.
Question 3
Solve the quadratic equation \( x^2 + 4x + 4 = 0 \) u\sing the quadratic formula.
Question 4
A sequence is defined by the recurrence relation \( a_n = 2a_{n-1} + 3 \). If \( a_1 = 2 \), find the value of \( a_{10} \).
Question 5
A surd is given by \( \sqrt{2} + \sqrt{3} \). Find the value of \( \sqrt{2} + \sqrt{3} \ \)^2 ).
Question 6
A binary operation ( odot ) is defined as \( a odot b = ab^2 \). Find the value of ( 2 odot 3 ).
Question 7
Find the equation of the \tangent line to the curve y = x^2 + 2x - 3 at the point (1, 2).
Question 8
A probability experiment consists of rolling two fair six-sided dice. What is the probability that the sum of the numbers on the dice is 7?
Question 9
Find the volume of the solid formed by revolving the region bounded by the curve \( y = x^2 \) and the line \( x = 2 \) about the x-axis.
Question 10
Let $X$ and $Y$ be indep\endent random variables with probability density functions $f_X(x) = egin{cases} 2x & 0 leq x leq 1 \ 0 & \text{otherwise} \end{cases}$ and $f_Y(y) = egin{cases} 3y^2 & 0 leq y leq 1 \ 0 & \text{otherwise} \end{cases}$. Find the probability that $X+Y leq 1$.
Question 11
Solve for x in the equation \( \frac{1}{x} + 2 = \frac{3}{x} \).
Question 12
Find the volume of the frustum of a cone with height 6 cm, lower base radius 4 cm, and upper base radius 2 cm.
Question 13
Find the derivative of the function $f(x) = \frac{x^2}{x^2 + 1}$ u\sing the chain rule.
Question 14
Find the area under the curve \( y = \frac{1}{2}x^2 + 3x - 2 \) from \( x = 0 \) to \( x = 4 \).
Question 15
Solve the inequality \( 2x^2 + 5x - 3 > 0 \).
Master the Exam!
You've seen a preview, but there are thousands more questions plus AI tutor to break down complex solutions.
Unlock Full Access
Available for Android & Windows