A simple harmonic motion is described by the equation $x(t) = A \cos $ \omega t + \phi $$. If the amplitude is $A = 2$ cm, the angular frequency is $\omega = 3$ rad/s, and the phase angle is $\phi = \frac{\pi}{4}$, determine the position $x$ of the particle at time $t = 1$ s.

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x = 2 \cos \left$ 3 + \frac{\pi}{4} \right $

Post Utme Abu 2025 Physics Question 14

A simple harmonic motion is described by the equation $x(t) = A \cos \( \omega t + \phi \)$. If the amplitude is $A = 2$ cm, the angular frequency is $\omega = 3$ rad/s, and the phase angle is $\phi = \frac{\pi}{4}$, determine the position $x$ of the particle at time $t = 1$ s.

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