Post Utme Aaua 2020 Biology Question 21

Practice objective / multiple choice question 21 from the 2020 Post Utme Aaua Biology examination.

Post Utme Aaua 2020 Biology Objective / Multiple Choice
Question 21 POST_UTME_AAUA • 2020 • BIOLOGY • objective

In a population of Escherichia coli, the average generation time is 30 minutes. If the population size is 10^6 cells, and the growth rate is 0.5 h^-1, what is the rate of increase of the population per hour?

Answer Options

Correct Answer A. \( 10^6 \times e^{0.5 \times 1} \)
B. \( 10^6 \times \( 1 + 0.5 \ \) )
C. \( 10^6 \times \( 1 - 0.5 \ \) )
D. \( 10^6 \times e^{-0.5 \times 1} \)
Correct Answer
A
Correct Option:
\( 10^6 \times e^{0.5 \times 1} \)

About This Question

This is Post Utme Aaua 2020 Biology Question 21. It is one of the objective questions from the 2020 Post Utme Aaua Biology examination.

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